2x^-2/5-x^-1/5=0

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Solution for 2x^-2/5-x^-1/5=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x^-2)/5-((x^-1)/5) = 0

2/5*x^-2-1/5*x^-1 = 0

t_1 = x^-1

2/5*t_1^2-1/5*t_1^1 = 0

2/5*t_1^2-1/5*t_1 = 0

DELTA = (-1/5)^2-(0*2/5*4)

DELTA = 1/25

DELTA > 0

t_1 = ((1/25)^(1/2)+1/5)/(2/5*2) or t_1 = (1/5-(1/25)^(1/2))/(2/5*2)

t_1 = 1/2 or t_1 = 0

t_1 = 0

x^-1+0 = 0

x^-1 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x należy do O

t_1 = 1/2

x^-1-1/2 = 0

1*x^-1 = 1/2 // : 1

x^-1 = 1/2

-1 < 0

1/(x^1) = 1/2 // * x^1

1 = 1/2*x^1 // : 1/2

2 = x^1

x = 2

x = 2

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